A book contains 250 pages. A boy read 20, 18 and 12 pages respectively in three consecutive days. What part of the book did he read in 3 days and what part of the whole book has yet to be read by him
Answers
Step-by-step explanation:
Given:-
A book contains 250 pages. A boy read 20, 18 and 12 pages respectively in three consecutive days.
To find:-
What part of the book did he read in 3 days and what part of the whole book has yet to be read by him?
Solution:-
Total number of pages in a book = 250
Reading pages in the first day by a boy = 20
Reading pages in the second day by the boy=18
Reading pages in the third day by the boy = 12
Total reading pages in the book in all three consecutive days
=20+18+12
=50
Total number of pages has been read by the boy = 50
The part of the reading pages in the total pages
=Reading pages / Total pages
= 50/250
=1/5
The boy read 1/5th part of the book .
Remaining pages = Total pages - Already read pages
=> 250-50
= 200
The part of the remaining pages
= Remaining pages / Total pages
= 200/250
= 20/25
=4/5
Answer:-
The boy read 1/5th of the book.
The boy has yet to be read 4/5th of the book.
Answer:
1st part solution.
- 20 +18+12 = 50
- Therefore 50/250 =1/5
- so he has read 1/5 part of the book .
2nd part solution.
- Number of pages left (left means not read)
- 250-50=200 (because he has read 50 pages)
- Therefore 200/250= 4/5
- so 4/5 part is still left ( left means not read)
thankyou. (Hope it will help you)
step by step explanation: