a book contains 92pages what is the probability that sum of the digits in the page number is 9
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Number of pages of the book = 92 Which are from 1 to 92 Number of possible outcomes = 92 ∴ Number of pages whose sum of its page is 9 = 10 i.e. 9, 18, 27, 36, 45, 54, 63, 72, 81, 90 P(E) = 10/92 = 5/46
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Answer:
Possible outcomes are 1,2,3,......91,92
Total number of outcomes=92
Let E be the event of getting the sum of digits in the page number 9
Events favourable to E are 09,18,27,36,45,54,63,72,81,90
hence p(E) = No. of favourable outcomes to event E/ Total number of outcomes
= 10/92
=5/46
#BAL #answerwithquality
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