a book exhibition was held for a four days in a school the number of tickets sold at a counter on first and second third and final day was repeatability 1094 1812 2050 and2751 find the total numbers of tickets sold on all four days
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Answered by
2
Answer:
Okay lets add. 1094+1812+2050+2751 will be equal to 7074 tickets.
Answered by
1
Answer:
ok we Will do first write the days series wise
Step-by-step explanation:
tickets sold in 1st day = 1094
tickets sold in 2nd day =1812
tickets sold in 3rd day = 2050
tickets sold in 4th day =2751
now we add the total number of tickets that are sold in these days
1094+1812+2050+2751 = 7507
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