A book exhibition was held for four day in a school. The number of tickets sold at the counter on the first,second,third and final day was respectively 1094, 1812, 2050, and 2751. Find the total number of tickets sold on all the four days.
Answers
here,
The number of tickets sold at the counter on the first day=1094
The number of tickets sold at the counter on the second day=1812
The number of tickets sold at the counter on the third day=2050
The number of tickets sold at the counter on the final day=2751
now,
total number of ticket sold = sum of all the tickets sold on each day
=1094+1812+2050+2751
=2906+2050+2751
=4956+2751
=7707
Hence, the total number of tickets sold on all the four days is 7707.
Answer: 7707
Step-by-step explanation:
No. of tickets sold on the 1st day = 1094
No. of tickets sold on the 2nd day= 1812
No. of tickets sold on the 3rd day= 2050
No. of tickets sold on the final day= 2751
1094
+1812
+2050
+ 2751
7707
∴ Total tickets sold were 7707