Math, asked by bhavupatel53768, 8 months ago

A book exhibition was held for four day in a school. The number of tickets sold at the counter on the first,second,third and final day was respectively 1094, 1812, 2050, and 2751. Find the total number of tickets sold on all the four days. ​

Answers

Answered by 07armyjam
22

here,

The number of tickets sold at the counter on the first day=1094

The number of tickets sold at the counter on the second day=1812

The number of tickets sold at the counter on the third day=2050

The number of tickets sold at the counter on the final day=2751

now,

total number of ticket sold = sum of all the tickets sold on each day

                                              =1094+1812+2050+2751

                                              =2906+2050+2751

                                              =4956+2751

                                              =7707

Hence, the total number of tickets sold on all the four days is 7707.

Answered by jlikithgopal
5

Answer: 7707

Step-by-step explanation:

No. of tickets sold on the 1st day = 1094

No. of tickets sold on the 2nd day= 1812

No. of tickets sold on the 3rd day= 2050

No. of tickets sold on the final day= 2751

                                   1094

                                 +1812

                                +2050

                                + 2751

                                 7707

∴ Total tickets sold were 7707

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