Math, asked by sk9236857, 4 months ago

A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.​

Answers

Answered by AbinayaManimaran
5

Step-by-step explanation:

= 1094+1812+2050+2751

=7707

Answered by jackzzjck
11

Answer:

\sf The \: Total\:  number \: of\:  tickets\:  sold \: in\:  the \: exhibition = 7707

Step-by-step explanation:

Total number of days for which the  book exhibition was held = 4 days.

Number of Tickets sold in first day = 1094.

Number of Tickets sold in second day = 1812.

Number of Tickets sold in third day = 2050.

Number of tickets sold in fourth day = 2751.

Total number of tickets sold on all the four days at the book exhibition will be =

Number of Tickets sold in first day + Number of Tickets sold in second day + Number of Tickets sold in third day + Number of tickets sold in fourth day

Total number of tickets sold on all the four days at the book exhibition =  1094 + 1812 + 2050 + 2751  

Total number of tickets sold = 7707 tickets

Similar questions