a borane on analysis found to contain 88.45% of boron in it.its empirical formula is
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Answer:
B5H7
Explanation:
element% moles
B. 88.45 = 88.45/10.8 = 8.182/8.182 = 1×5
H - 11.55 = 11.5/1 = 11.5/8.182 = 1.40×5
answer:-B5H7
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