Question

A borrows 8000 at 12% per annum simple interest abd B borrows 9100 at 12% per annum simple interest. in how many years will their amount be equal.



PLEASE EXPLAIN FOR THE BEST RATING ​

Answer 1

Answer:

SI

A

Amount - 8000

Rate 12%

Let year x

⇒ Amount = SIA+PA

⇒1008000×12×x

B

Amount 9100

Rate 10%

let year x

AmountB=SIB+PB

1009100×10×x

⇒960x+8000=910x+9100

960x−910x=9100−8000

50x=1100

x=22

After 22 yeras, Amount will be equal

Answer 2

SI of

A

Amount - 8000 Rs

Rate 12%

Let year be  x

⇒ Amount = {SI(A) +P(A)}

​ ⇒   (8000×12×x) / 100                ( Eq 1 )

​

same of  

B

Amount 9100 Rs

Rate 10%

let year be  x

Amount  (B)​  =  SI  (B)  + P  (B)

​                      =   (9100 × 10× x) / 100           (Eq 2)

on solving equation 1 and 2 we get :

​                      =960x+8000=910x+9100

                    =960x−910x=9100−8000  

                    =50x=1100

  Therefore   x=22

After 22 years, Amount will be equal.