a borrows 8000 rupees at 12% per annum simple interest and B borrows 9100 Rupees at 10% per annum simple interest in how many years will their amounts be equal?
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SI
A
Amount - 8000
Rate 12%
Let year x
⇒ Amount = SI
A
+P
A
⇒
100
8000×12×x
B
Amount 9100
Rate 10%
let year x
Amount
B
=SI
B
+P
B
100
9100×10×x
⇒960x+8000=910x+9100
960x−910x=9100−8000
50x=1100
x=22
After 22 yeras, Amount will be equal
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