Question

a borrows rupees 8000 at 12% per annum simple interest and B borrows rupees 9100 at 10% per annum simple interest in how many years will there amount be equal

Answer 1

Answer:

Let in x yr. amount be equal.

so,

$8000 + \frac{8000 \times 12 \times x}{100} = 9100 + \frac{9100 \times 10 \times x}{100}$

$8000 + 960x = 9100 + 910x$

$960x - 910x = 9100 - 8000$

$50x = 1100$

$x = \frac{1100}{50} = 22 \: yeaes.$