Math, asked by monikaaswal8283, 1 year ago

A boss decides to distribute Rs. 2000 between 2 employees. He knows X deserves more that Y, but does not know how much more. So he decides to arbitrarily break Rs. 2000 into two parts and give X the bigger part. What is the chance that X gets twice as much as Y or more?
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Answers

Answered by harpalsingh000177
4

Answer:

D

Step-by-step explanation:

The bigger part could be any number from 1000 to 2000.  

Now, if the bigger part is to be at least twice as much as the smaller part, we have  

X ≥ 2Y or X ≥ 2(2000 – X)  

Or X ≥ 4000/3

Given that X lies between 1000 and 2000, what is the probability that X lies between 4000/3 and 2000?

This probability is equal to (2000−4000/3)/(2000−1000) = 2/3

The question is "What is the chance that X gets twice as much as Y or more?"

Hence the answer is "2/3"

Answered by amitnrw
3

Answer:

2/3

Step-by-step explanation:

Bigger part 1001 to 1999

Smaller part 999 to 1

total 999

Bigger part ≥ 2Smaller part

Bigger Part + smaller Part = 2000

=> Bigger Part + bigger part/2 ≥ 2000

=> 3 bigger part ≥ 4000

=> Bigger Part  ≥ 4000/3

1334 -  1999 = 666 Part

Probability = 666/999 = 2/3

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