A boss decides to distribute Rs. 2000 between 2 employees. He knows X deserves more that Y, but does not know how much more. So he decides to arbitrarily break Rs. 2000 into two parts and give X the bigger part. What is the chance that X gets twice as much as Y or more?
\\frac{2}{5}\\)
\\frac{1}{2}\\)
\\frac{1}{3}\\)
\\frac{2}{3}\\)
Answers
Answer:
D
Step-by-step explanation:
The bigger part could be any number from 1000 to 2000.
Now, if the bigger part is to be at least twice as much as the smaller part, we have
X ≥ 2Y or X ≥ 2(2000 – X)
Or X ≥ 4000/3
Given that X lies between 1000 and 2000, what is the probability that X lies between 4000/3 and 2000?
This probability is equal to (2000−4000/3)/(2000−1000) = 2/3
The question is "What is the chance that X gets twice as much as Y or more?"
Hence the answer is "2/3"
Answer:
2/3
Step-by-step explanation:
Bigger part 1001 to 1999
Smaller part 999 to 1
total 999
Bigger part ≥ 2Smaller part
Bigger Part + smaller Part = 2000
=> Bigger Part + bigger part/2 ≥ 2000
=> 3 bigger part ≥ 4000
=> Bigger Part ≥ 4000/3
1334 - 1999 = 666 Part
Probability = 666/999 = 2/3