Question

A bot 10 bundles of 12 books and each bundle costs Rs.2880 but b also bought the same books but 15 bundles of 10 box each how much money should b paid ???

Answer 1

$]\huge{\mathcal{\purple{A}\green{N}\pink{S}\blue{W}\purple{E}\green{R}\pink{!}}}$

• Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)]
• Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)]
• Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26.
• Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26.
• Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26. let the price of one book be Rs. x
• Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26. let the price of one book be Rs. x
• Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26. let the price of one book be Rs. x Then, the price of other book = Rs. (x + 60% of x) = Rs.(x+(3/5)x) = Rs. (8/5)x
• Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26. let the price of one book be Rs. x Then, the price of other book = Rs. (x + 60% of x) = Rs.(x+(3/5)x) = Rs. (8/5)x
• Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26. let the price of one book be Rs. x Then, the price of other book = Rs. (x + 60% of x) = Rs.(x+(3/5)x) = Rs. (8/5)x So, x+(8/5)x =26 <=> x =10
• Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26. let the price of one book be Rs. x Then, the price of other book = Rs. (x + 60% of x) = Rs.(x+(3/5)x) = Rs. (8/5)x So, x+(8/5)x =26 <=> x =10
• Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26. let the price of one book be Rs. x Then, the price of other book = Rs. (x + 60% of x) = Rs.(x+(3/5)x) = Rs. (8/5)x So, x+(8/5)x =26 <=> x =10 The prices of the two books are Rs. 10 and Rs. 16

Answer 2

Answer:

$\huge{\mathcal{\purple{A}\green{N}\pink{S}\blue{W}\purple{E}\green{R}\pink{!}}}!$

Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)]

Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)]

Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26.

Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26.

Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26. let the price of one book be Rs. x

Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26. let the price of one book be Rs. x

Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26. let the price of one book be Rs. x Then, the price of other book = Rs. (x + 60% of x) = Rs.(x+(3/5)x) = Rs. (8/5)x

Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26. let the price of one book be Rs. x Then, the price of other book = Rs. (x + 60% of x) = Rs.(x+(3/5)x) = Rs. (8/5)x

Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26. let the price of one book be Rs. x Then, the price of other book = Rs. (x + 60% of x) = Rs.(x+(3/5)x) = Rs. (8/5)x So, x+(8/5)x =26 <=> x =10

Total pice of the two books = Rs. [(12 x 10) - (11.75 x 8)] = Rs. (120 - 94) = Rs. 26. let the price of one book be Rs. x Then, the price of other book = Rs. (x + 60% of x) = Rs.(x+(3/5)x) = Rs. (8/5)x So, x+(8/5)x =26 <=> x =10