A bottle contain 5 litres so how much water is required to fill the tank that is 120.25 liter
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Answer:
Quantity of water in tank A = 5x Quantity of water in tank B= x
Total quantity of water= 6x 6x= (45+45) litres 6x = 90 litres x = 15 litres A=5X=75 LITRES, B = 15 LITRES Quantity of water transfe from A to B = 30
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- Fill up B all the way up to its brim.= Now we have 3L in B and no water in A.
- Decant the contents of B into A.= We now have 3L of water in A while B is empty.
- We now have 3L of water in A while B is empty.Fill up B again. We now have 3L in both the containers
- . Decant the contents of B into A until A is full. Container A already has 3L in it. Since, its maximum capacity was 4L, it can still accommodate 1 L of water. Container B has 3L and when you useit to fill up A, only 1L is transferred before A fills up. Leaving 2L of water in B.
hope it will help you
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