Question

A bottle is heated with its mouth open to have a final temperature as 5 times its original value at 27



c. The fraction of air originally present in the bottle that is expelled is

Answer 1

Answer:

33%

Explanation:

27°C= 27+273= 298 Kelvin  

Let at temperature1 (T1), volume = 1 litre

When ⅓ air escapes out, air left = ⅔ litre  

use V1T1= V2T2

Therefore

V2 =V1T2/T1 = V1*398/298 = 1.33V1

therefore the volume expelled air = V1(1.33-1) = 0.33V1

The fraction of expelled air 0.33V1/V1 = 0.33 or 33%