A bottle which contains 200 ml of 0.1 m koh, absorbs 1 millimole of co2
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We first write the equation of the reaction.
2 KOH (aq) + CO₂ (g) —> K₂CO₃ (aq) + H₂O (l)
The mole ratio of KOH : K₂CO₃ is : 2:1
Given that the moles of CO₂ dissolved is 0.001 moles, we can get the volume of CO₂ dissolved.
1 mole of CO₂ is 22400 cm³ at stp.
Therefore :
0.001 × 22400 = 22.4 cm³
The total volume of the resulting solution is thus :
200 + 22.4 = 222.4 cm³
The moles of KOH in 200 cm³ is :
(200/1000) × 0.1 = 0.02 moles.
The mole ratio is 2 : 1
Thus moles of KCO₃ is : 0.02/2 = 0.01 moles.
The resulting solution is 222.4cm ³ thus the molarity of KCO₃ is :
[1000 /222.4] × 0.01 = 0.04496 M
2 KOH (aq) + CO₂ (g) —> K₂CO₃ (aq) + H₂O (l)
The mole ratio of KOH : K₂CO₃ is : 2:1
Given that the moles of CO₂ dissolved is 0.001 moles, we can get the volume of CO₂ dissolved.
1 mole of CO₂ is 22400 cm³ at stp.
Therefore :
0.001 × 22400 = 22.4 cm³
The total volume of the resulting solution is thus :
200 + 22.4 = 222.4 cm³
The moles of KOH in 200 cm³ is :
(200/1000) × 0.1 = 0.02 moles.
The mole ratio is 2 : 1
Thus moles of KCO₃ is : 0.02/2 = 0.01 moles.
The resulting solution is 222.4cm ³ thus the molarity of KCO₃ is :
[1000 /222.4] × 0.01 = 0.04496 M
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