Math, asked by saritajaisawal171971, 1 year ago

A bought a car for 100000 and spent 10000 on its repairs. He sold this car to B at a gain of 10% who later on sold it to C at a gain of 5%.What did C pay for the car?

Answers

Answered by debtwenty12pe7hvl

⇒CP for A = Purchase Price + Cost of Repair

⇒CP for A= 100000 + 10000 = Rs. 1,10,000/-

⇒Gain for A 10%

⇒SP of A = CP of B = 110000( 1+10/100)

= 110000* 110/100

= Rs. 121000/-

⇒Gain for B= 5%

⇒SP of B = CP for C = 121000(1+5/100)

= 121000* 105/100

= Rs 127050/-

∴ C has to Pay Rs. 1,27,050/- for the car Ans

saritajaisawal171971: sir please solve this problem -The cost price of 12 candles is equal to the selling price of 15 candles. Find the loss percent

debtwenty12pe7hvl: let cp of 12 candles be rs 12x now sp of 15 candle will also be rs 12x. so sp of 1 candles is 12x/15. now sp of 12candle=12x/15*12=48x/5 [do unitary method]. now profit=sp-cp =12x -48x/5 =12x/5 now p%=p/cp *100=[12x/5] ÷12x*100= 20%

debtwenty12pe7hvl: hope this will help u

saritajaisawal171971: thanks sir

debtwenty12pe7hvl: sorry i think i made a mistake in a hurry as u mentioned there is loss let me recheck it

debtwenty12pe7hvl: sorry there is loss so just correct loss =cp-sp in place of sp-cp and L%=L/cp*100 in place of p%=p/cp *100 rest will be same

debtwenty12pe7hvl: now loss=cp-sp =12x -48x/5 =12x/5 now L%=L/cp *100=[12x/5] ÷12x*100= 20% loss

Answered by sambhav840karn

Answer:

Step-by-step explanation:

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