A bought a car for 100000 and spent 10000 on its repairs. He sold this car to B at a gain of 10% who later on sold it to C at a gain of 5%.What did C pay for the car?
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⇒CP for A = Purchase Price + Cost of Repair
⇒CP for A= 100000 + 10000 = Rs. 1,10,000/-
⇒Gain for A 10%
⇒SP of A = CP of B = 110000( 1+10/100)
= 110000* 110/100
= Rs. 121000/-
⇒Gain for B= 5%
⇒SP of B = CP for C = 121000(1+5/100)
= 121000* 105/100
= Rs 127050/-
∴ C has to Pay Rs. 1,27,050/- for the car Ans
saritajaisawal171971:
sir please solve this problem -The cost price of 12 candles is equal to the selling price of 15 candles. Find the loss percent
let cp of 12 candles be rs 12x now sp of 15 candle will also be rs 12x. so sp of 1 candles is 12x/15. now sp of 12candle=12x/15*12=48x/5 [do unitary method]. now profit=sp-cp =12x -48x/5 =12x/5 now p%=p/cp *100=[12x/5] ÷12x*100= 20%
hope this will help u
thanks sir
sorry i think i made a mistake in a hurry as u mentioned there is loss let me recheck it
sorry there is loss so just correct loss =cp-sp in place of sp-cp and L%=L/cp*100 in place of p%=p/cp *100 rest will be same
now loss=cp-sp =12x -48x/5 =12x/5 now L%=L/cp *100=[12x/5] ÷12x*100= 20% loss
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