Question

A' bought a certain quantity of mangoes at total cost of rs. 2100. he sold 2⁄7th of the mangoes at 5% loss. if ‘a' incurs an overall loss of 10%. at what percent loss did ‘a' sell the rest of the mangoes

Answer 1

Let C.P. of each orange be Rs.100.

Number of oranges =2100÷100=21.

S.P. of 21 oranges =(2100x90)÷100=1890.

2⁄7th of the mangoes that is $\frac{2}{7}x21=6.$mangoes are sold at 5% loss.

S.P=(6x100x95)÷100=570.

Therefore, Required S.P. of remaining 15 oranges=1890-570=1320.

Percent loss$\frac{1500-1320}{1320}x100=13.6%$%

Answer 2

Answer:

12%

Step-by-step explanation:

solving by mixture and allegation

2/7             5/7

(-5%)             x

         (-10%)

-2                     -5

2          :            5

so  x -(-10) =-2

     x=-12

so a sells the rest of mangoes i.e 5/7 at 12% loss