Question

A bouncing ball reaches a max. Height of 10m. How much time does each complete up and down cycle take??

Answer 1

H = 10 m
10 = 1/2 * (10)* t^2 (Second equation of motion)
t = Root 5 s

Since it goes up and comes down again, time take = 2 Root 5 s

Answer 2

Answer:

2.857 s

Explanation:since maximum height is 10 m

U^2/2g =10

U=14 m/s

Again total time =2u/g

=2×14/9.8(g=9.8)

=2.857 s