Question

A bouquet shop has roses, tulips, and dahlias in 5:6:7 ratio. If there are 4680 flowers, find the no. of flowers for each variety.

Answer 1

Answer:

There are 1300 roses, 1560 tulips, and 1820 dahlias.

Step-by-step explanation:

5:6:7

Sum of all terms = 18

First term = 5/18 x 4680 = (reduced) 5/1 x 260 = 1300

Second term = 6/18 x 4680 = (reduced) 6/1 x 260 = 1560

Third term = 7/18 x 4680 = (reduced) 7/1 x 260 = 1820

Therefore, there are 1300 roses, 1560 tulips, and 1820 dahlias.

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Answer 2

Question -

A bouquet shop has roses, tulips and dahlias in 5:6:7 ratio. If there are 4680 flowers, find the no. of flowers for each variety.

Answer -

Let the ,

• Roses - 5x
• Tulips - 6x
• dahlias - 7x

We know that

• Total no. of flowers = 4680

To find

• No. of flowers for each variety.

It is given to us that total number of flour is 4680 therefore ,

$: \Longrightarrow\sf{ 5x + 6x + 7x = 4680}$

$: \Longrightarrow\sf{ 18x = 4680}$

$: \Longrightarrow\sf{ x = \dfrac{ 4680}{18}}$

$: \Longrightarrow\sf{ x =260 }$

Now putting the values ,

★ Roses - 5x

$: \Longrightarrow\sf{ 5 \times 260 = 1300 }$

★ Tulips - 6x

$: \Longrightarrow\sf{ 6\times 260 = 1560 }$

★ dahlias - 7x

$: \Longrightarrow\sf{ 7\times 260 = 1820 }$