Question

A bow can shoot a 0.042 kg arrow at a speed of 16.5m/s. What is the kinetic energy of the arrow?

Answer 1

0.693 JOULE(0.042*16.5) UNDERSTOOD?

Answer 2

The kinetic energy of the arrow is 5.71725 joule

Solution:

The kinetic energy is given by formula:

$K.E = \frac{1}{2} \times mv^2$

Where,

m = mass ( kg )

v = velocity ( m /s)

KE = kinetic energy ( joule )

From given,

m = 0.042 kg

v = 16.5 m/s

Therefore,

$KE = \frac{1}{2} \times 0.042 \times 16.5^2\\\\KE = 0.021 \times 272.25\\\\KE = 5.71725\ joule$

Thus, kinetic energy of the arrow is 5.71725 joule

Learn more:

The kinetic energy of N molecules of H2 is 3J at -73°c. The kinetic energy of the same sample of H2 at 127°c is

https://brainly.in/question/12334877

If the kinetic energy of body becomes 256 times of its initial value, then new momentum will

https://brainly.in/question/5756416