Question

A bowl of sweets was placed on a table to be distributed among three brothers rajan, sajal and karan. Rajan arrived first and ate what he thought was his share of sweets and left. Then, sajal arrived. He thought that he was the first one to arrive and ate the number of sweets, he thought was his share and left. Lastly, karan arrived. He again thought he was the first one to arrive and he took what he thought was his share. If 16 sweets are left in the bowl finally, how many sweets did the bowl contain initially?

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

The bowl contained 54 sweets

Step-by-step explanation:

Given :

Let assume there were 54 sweets.

Step 1:

First Rajan came and he thought that we are 3 brothers and have to eat equal sweets and decided to eat 54/3 sweets that is 18 sweets.

Step 2:

Left sweets are 36 sweets.

Step 3:

Then sejal came similarly he ate 36/3 sweets that is 2 sweets.

Step 4:

Left sweet are 24.

Step 5:

Then same for Karan 24/ 3 = 8.

Left sweets are 24 – 8 =16.

Hence verified total sweets are 54.