A bowler bowled at a speed of 40m/s. An Indian cricketer hits the ball, it's moves in opposite direction with a speed of 60m/s. What is the acceleration of the ball if time taken is 10s???
Answers
Answer:-
- 2m/s² is the required acceleration.
Given:-
- Initial velocity ,u = 40m/s
- Final velocity ,v = 60m/s
- Time taken ,t = 10s
To Find:-
- Acceleration of the ball ,a
Solution:-
According to the Question
It is given that bowler bowled at a speed of 40m/s. An Indian cricketer hits the ball, it's moves in opposite direction with a speed of 60m/s.
We have to calculate the acceleration of the ball.
As we know that acceleration is defined as the rate of change in velocity.
- a = v-u/t
where,
- v is the final velocity
- a is the acceleration
- u is the initial velocity
- t is the time taken
Substitute the value we get
→ a = 60-40/10
→ a = 20/10
→ a = 2m/s²
- Hence, the acceleration of the ball is 2m/s².
Given :-
A bowler bowled at a speed of 40m/s. An Indian cricketer hits the ball, it's moves in opposite direction with a speed of 60m/s
To Find :-
Acceleration of the ball if time taken is 10s
Solution :-
We know that
v = u + at
60 = 40 + a(10)
60 = 40 + 10a
60 - 40 = 10a
20 = 10a
20/10 = a
2 = a
Hence
Acceleration is 2 m/s²
Know More :-
Equations of motion
1st equation ⇒ v = u + at
2nd equation ⇒ s = ut + 1/2 at²
3rd equation ⇒ v² - u² = 2as
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