Question

A bowler releases a 7 kgbowling ball from rest to a final velocity of 8 m/s.What is the magnitude of the change in momentum of the bowling ball?

Answer 1

Explanation:

Mass of ball (m)= 7 kg

initial velocity (u)= 0m/s

final velocity (v) = 8m/s

Initial momentum = m*u

=7*0 kg m/s

=0 kg m/s

final momentum= m*v

= 7*8 kg m/s

=56 kg m/s

Change in momentum= 56 -0 kg m/s

= 56 kg m/s

Ans =56 kg m/s

Answer 2

Answer:  p(momentum) =m(mass) * v(velocity)  => 7kg*8m/s => 56 kg m/s => 56 N

kg m/s can also be said as N, which means Newtons.

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