a bowler throwing a ball in a cricket match with a speed of 143 kilometre per hour and distance of boundary from batsman is 63 metre. find the force applied by the batsman so that he can hit this six
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Answer: A bowler throws a ball at a speed = 143km/hr
So, the speed of ball after conversion to m/s = 143*1000/3600
= 143*5/18 = 715/18 = 39.72m/s
So the force applied to hit the ball = 63/39.72 = 6300/3972
= 1.58N
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