Physics, asked by himanipatel349, 4 months ago

A bowling ball is lifted to a height such that its gravitational potential energy is 20 joules relative to the ground. If released from rest, how much kinetic energy does the ball have just before striking the ground?
Ignore air resistance.

Answers

Answered by kanthikiran3
3

Answer:

Kf= 20J

Explanation:

Friction mechanical energy is conserved

Ei = Ef

Ki+Pi = Kf+Pf

0+20=Kf+0

Kf=20J

Answered by tiwariakdi
0

Kinetic energy = 20 joules.

  • The energy an object has as a result of motion is known as kinetic energy.
  • A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed. Kinetic energy is the type of energy that is transferred and is dependent on the mass and speed attained.
  • Kinetic energy can be converted into other types of energy and transported between objects. A flying squirrel may run into a chipmunk that is standing still, for instance. Some of the squirrel's initial kinetic energy may have been transferred to the chipmunk or changed into another kind of energy after the collision.

Here, according to the given information,

A bowling ball is lifted to a height such that its gravitational potential energy is 20 joules relative to the ground.

Then, we know that,

0 + 20 = KE + 0.

Or, Kinetic energy = 20 joules.

Hence, Kinetic energy = 20 joules.

Learn more here

https://brainly.in/question/13042527

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