Question

A bowling ball maker starts with an 8.5 inch diameter resin sphere and drills 3 cylindrical finger holes in it. each hole is 1 inch in diameter and 3.5 inches deep. which is the best estimate of the volume of resin in the finished ball

Answer 1

Given:

Diameter of the bowling ball = 8.5 inches

There are 3 cylindrical finger holes.

Each hole is 1 in in diameter and 3.5 inches deep.

To Find:

The estimated volume of the finished ball

Solution:

Find the volume of the sphere of diameter 8.5 inches:

Volume = 4/3 πr³

Volume = 4/3 π(8.5 ÷ 2)³

Volume = 321.60 in³

Find the volume of the 3 finger holes:

Volume = πr²h

Volume of 1 finger hole = π(1 ÷ 2)²(3.5)

Volume of 1 finger hole = 2.75 in³

Volume of 3 finger holes = 2.75 x 3

Volume of 3 finger holes = 8.25 in³

Find the volume of the bowling ball:

Volume of the bowling ball = 321.60 - 8.25

Volume of the bowling ball = 313.35 in³

Answer: 313.35 in³

Answer 2

Answer:

$\implies$ 313.35 inches ³

$\large\underline\mathrm{Given:-}$

$\implies$ Diameter = 8.5 inch6

$\implies$ There are the three cylindrical holes. each holes in 1 inches diameter and 3.5 inches deep.

$\large\underline\mathrm{To \: find}$

The estimated vol. of the finished ball.

$\large\underline\mathrm{Solution}$

$\implies$ The vol. of the sphere of diameter 8.5 inches.

$\implies$ vol. = 4/3 πr³

$\implies$ 4/3 π(8.3/2)³

$\implies$ 321.60 inches ³

The Vol of the 3 figure holes:

$\implies$ Vol. = πr²h

$\implies$ 22/7 × 1/2 × 1/2 × 3.5

$\implies$ 2.75 inches ³

Vol. of the bowling ball = 321.60 - 8.25

$\implies$ 313.35 inches ³