Question

A box at rest starts sliding down an enclined plane for 3 seconds,until it teaches a velocity of a 27 m/s.What is the boxes accelaration?​​​

Answer 1

Answer:

9 m/s²

Explanation:

First we should write what we are provided with-

Here,

Time (t) = 3 s

Final velocity (v) = 27 m/s

Initial velocity (u) = 0 ( because the question states that the box "starts" sliding down, this means it was at rest sometime ago.)

We have to find the acceleration of the box here.

By

$a = \frac{v - u}{t}$

Putting values,

a = 27/3

→ a = 9 m/s²

The the acceleration of the box is 9 m/s²