A box contain 10 red balls , 7 green balls and 12 blue balls . a ball drawn at random .what is the probability that the ball drawn is either red nor green?
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Answered by
1
total number of balls=10+7+12=29
total number of red balls=10
total number of green balls=7
probability of red and green balls =10/29+6/29= 17/29
probability of nor red or nor green= 1-17/29
= 29-17/29 =12/29
total number of red balls=10
total number of green balls=7
probability of red and green balls =10/29+6/29= 17/29
probability of nor red or nor green= 1-17/29
= 29-17/29 =12/29
Answered by
0
Answer:
17/29
Step-by-step explanation:
no need no subtract 1 from 1-17/29
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