Question

A box contain 15 red 25 blue and 10 green coloured balls. if a ball is picked from this box at random , Find the probability that the ball picked is :

a) red

b) blue

c) red or blue

d) green

e) Not green​

Answer 1

Given:-

⠀

A box contain 15 red 25 blue and 10 green coloured balls. if a ball is picked from this box at random.

⠀

To Find:-

⠀

the probability that the ball picked is :

a) red

b) blue

c) red or blue

d) green

e) Not green

⠀

STEP BY STEP EXPLANATION:-

⠀

Total Number of balls = 15 + 25 + 10 = 50

⠀

a) Number of red balls = 15

$\sf p(picking \: a \: red \: ball) = </p><p></p><h3>\frac{15}{50} = \frac{3}{10}$

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b) Number of blue balls

$\sf p(picking \: a \: blue\: ball) = \frac{25}{50} = \frac{1}{2}$

⠀

c) Number of red or blue balls = 15 + 25 = 40

$\sf p(picking \: a \: red \: or \: blue\: ball) = \frac{40}{50} = \frac{4}{5}$

⠀

d) Number of green balls = 10

$\sf p(picking \: a \: green \: ball) = \frac{10}{50} = \frac{1}{5}$

⠀

e) p(not picking a green ball) = 1 - p(picking a green ball) = 1 $\sf- \frac{1}{5} = \frac{4}{5}$

Answer 2

GIVEN :–

• A box contain 15 red 25 blue and 10 green coloured balls.

TO FIND :–

• If a ball is picked from this box at random , Find the probability that the ball picked is –

a) red

b) blue

c) red or blue

d) green

e) Not green

SOLUTION :–

• We know that –

$\\ \bf \to \: Probability = \dfrac{n(E)}{n(S)}$

• Here –

$\\ \bf \implies n(S) = 15 + 25 + 10 = 50$

(a) Picked ball is red –

$\\ \bf \implies n(E) = 15$

• So that –

$\\ \bf \implies\: Probability = \cancel\dfrac{15}{50}$

$\\ \large\implies\:{ \boxed{ \bf Probability = \dfrac{3}{10}}}$

(b) Picked ball is blue –

$\\ \bf \implies n(E) = 25$

• So that –

$\\ \bf \implies\: Probability = \cancel\dfrac{25}{50}$

$\\ \large\implies\:{ \boxed{ \bf Probability = \dfrac{1}{2}}}$

(c) Picked ball is red or blue –

$\\ \bf \implies n(E) = 15+25=40$

• So that –

$\\ \bf \implies\: Probability = \cancel\dfrac{40}{50}$

$\\ \large\implies\:{ \boxed{ \bf Probability = \dfrac{4}{5}}}$

(d) Picked ball is green –

$\\ \bf \implies n(E) = 10$

• So that –

$\\ \bf \implies\: Probability = \cancel\dfrac{10}{50}$

$\\ \large\implies\:{ \boxed{ \bf Probability = \dfrac{1}{5}}}$

(e) Picked ball is not green, It means ball should be red or blue –

$\\ \bf \implies n(E) = 15+25=40$

• So that –

$\\ \bf \implies\: Probability = \cancel\dfrac{40}{50}$

$\\ \large\implies\:{ \boxed{ \bf Probability = \dfrac{4}{5}}}$