A box contain 2 black 3 red and 4 blue balls two balls are drawn randomly from the bag what is the probability that second ball drawn is red
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Total number of balls = (2 + 3 + 2) = 7.
Let S be the sample space.
Then, n(S) = Number of ways of drawing 2 balls out of 7 =7C27C2 = 21
Let E = Event of drawing 2 balls, none of which is blue.
n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls =5C25C2 = 10
Therefore, P(E) = n(E)/n(S) = 10/ 21.
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