Question

A box contain 2 blue caps , 4 red caps, 5 green caps and 1 yellow caps. If two caps are picked at random then what is the probability that atleast one is red?

Answer 1

Answer:

1/3

Step-by-step explanation:

Total number of caps:12

Probability of at least picking one red cap is 1/3

Answer 2

0.5758 (aprrox. $\dfrac{1}{3}$)

Given:-

• No. of blue caps = 2

• No. of red caps = 4

• No. of green caps = 5

• No. of yellow caps = 1

To Find:-

• If two caps are picked at random then what is the probability that atleast one is red?

Solution:-

• Total no. of caps = 12.

✠ First time you pick a cap,

there are (2 + 4 + 5 + 1) = 12 choices,

✠ Second time you pick a cap,

there are (12 - 1) 11 choices

⍟ So, the total possible combination is (12 × 11) = 132 choices by multiple principal.

★ The possible combination that there are not red caps in your two choices

is (12 - 4) × (11 - 4) = 8 × 7 = 56,

⍟ So,

$\star \;\sf \purple{Probability}_{( at\;least\;one\;is\;red)} = \dfrac{(132 - 56)}{132}$

= 0.5758 (aprrox. $\dfrac{1}{3}$)

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