Question

a box contain 3 red and 7 white balls is drawn at random its place a ball of other colour is put in the box now the ball is drawn ata random from the box find the probability of it is red ball
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Answer 1

Answer:

$\frac{3}{11}$

Step-by-step explanation:

No: of red balls = 3

No: of white balls = 7

One ball of other colour is put in

Total no: of balls = 7+3+1

= 11

P(of getting red colour ball) =

$\frac{no \: of \: red \: balls}{total \: no \: of \: balls }$

$\frac { 3}{11}$

Answer 2

Answer:

3/11 is the probability of getting red ball .

Step-by-step explanation:

• Total number of balls = 3+7=10.
• Red balls =3
• White balls=7
• unknown colour =1

now total number of balls in the box = 10+1=11.

probability of getting a red ball= total number of red balls/total number of balls in the box.

=3/11

(#SPJ2)