Question

A box contain 4 black beads and 3 white beads.Another box contain 5 black beads and 7 white beads .One bead taken from each. a) write tge the number possible pairs. b) What is the probability of both being black. c) what is the probability of both one black and one white. d) what is the probability of getting at least one black beads.

Answer 1

Answer:

Step-by-step explanation:

a =17/35

b = 3/7

Step-by-step explanation:

solution----->

Given:-

box A = 8 black beads and 12 white beads

Box B = 9black and 6 white beads

as per condition

S = {B,B,B,B,B,B,B,W,W,W,W,W,W,W,W,W,W,W,W

B,B,B,B,B,B,B,B,B,W,W,W,W,W,W}

n (s)= 35

now as per first condition

A = {B,B,B,B,B,B,B,B,B,B,B,B,B,B,B,B,B}

n (A)= 17

acording to 2nd condition

B ={B,B,B,B,B,B,B,B,W,W,W,W,W,W}

n (B)= 15

Answer 2

Answer:

a =17/35

b = 3/7

Step-by-step explanation:

solution----->

Given:-

box A = 8 black beads and 12 white beads

Box B = 9black and 6 white beads

as per condition

S = {B,B,B,B,B,B,B,W,W,W,W,W,W,W,W,W,W,W,W

B,B,B,B,B,B,B,B,B,W,W,W,W,W,W}

n (s)= 35

now as per first condition

A = {B,B,B,B,B,B,B,B,B,B,B,B,B,B,B,B,B}

n (A)= 17

acording to 2nd condition

B ={B,B,B,B,B,B,B,B,W,W,W,W,W,W}

n (B)= 15