Question

A box contain 4 red balls, 7 white balls and 11 green balls. One ball is taken out of
the box at random. What is the probability that the ball taken out will be (i) white
? (ii) not red?

Answer 1

☞Solution :-

Probability of getting white balls = No. of white balls / total no. of balls

$= \frac{7}{22}$

So,

The probability of getting white ball is 7/22.

Probability of getting not red balls = Not red balls / total no. of balls

$= \frac{18}{22}$

So,

The probability of getting not red balls is 18 /22.

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Hopes, it's helpful.

ItzNobita5 ^_^