Question

a box contain 4 white and 2 green balls .in 2 successive draws the probability that both ball are white is?​

Answer 1

Answer:

Total outcomes = 4+2 = 6

Favourable Outcomes = 4 [White Balls]

Therefore, Probability that both ball are white is =

$\frac{4}{6} = \frac{2}{3}$

Answer 2

Answer:

The probability that both the balls will be white is 2/5

Explanation:

Given data :

4 white balls and 2 green balls

To be calculated :

The balls are successively drawn, the probability that both the balls are white.

Formula to be Used :

$probability \: of \: an \: event \: = \frac{number \: of \: favorable \: outcomes}{total \: number \: of \: outcomes \: }$

Calculations :

For the 1 case when balls is drawn for the first time,

Total number of observations = number of white balls + number of green balls = 4+2 = 6

Number of favourable outcomes = 4

Let probability of getting the white ball in first go be E, then

$E = \frac{4}{6} = \frac{2}{3}$

Now, for the second case, the probability of drawing the balls for the second time, then

Number of favourable outcomes = 3

Total number of observations = 5

Let e be the probability of getting the white ball in second time, then,

$e = \frac{3}{5}$

Now, the probability that both the balls will be white is,

$probability \: that \: both \: the \: balls \: are \: white \: = \frac{2}{3} \times \frac{3}{5} = \frac{2}{5} = 0.4$

Hence , the probability that both the balls will be white is 2/5

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