Question

A box contain 7 black balls and 3 red balls. A ball is drawn out at random. Find probability of getting (i) a red ball. (ii) Neither a red nor a black.

Fast... pls...

Answer 1

red ball =p(a)=n(a)/n(s)
=3/10
not red or black =p(b)=n(b)/n(s)
=0/10=0

Answer 2

Answer:

(i) 3/10  (ii) 0

Step-by-step explanation:

Number of black balls = 7

Number of red balls = 3

Total number of balls = no. of possible outcomes = (7 + 3) = 10

(i) Let E1 be the event of getting a red ball

Then, no. of favourable outcomes = 3

Probability of getting a red ball P(E1) = 3/10

(ii) Let E2 be the event of getting neither a black ball nor a red ball

Then, no. of favourable outcomes = 0

Probability of getting neither a black nor a red ball P(E2) = 0/10 = 0