Question

A box contain 7 red , 6 white and 4 blue balls. How many selections of 3 balls can be made so that 1) all 3 balls are red balls 2) none is red balls 3) there is one ball of each colour​

Answer 1

Answer:

120 is correct answer

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

Given, white ball =4

Red ball =6

Black ball =7

Blue ball =3

Total number of balls =20

Therefore, n(S) =20

(i) Let A be event of getting neither White nor Black ball.

⇒n(A)=6+3=9