Question

A box contain 9 tickets numbered from 1 to 9. If 3 tickets are drawn from the box, one by one then probability that the numbers on these are alternately either even, odd, even or odd; even, odd is

Answer 1

5 odd and 4 even

o-e-o: 5/9*4/8*4/7=80/504 or 0.1587

e-o-e: 4/9*5/8*3/7=60/504=0.1190