a box contain cards bearing number form 6 to 70if one card is drawn at random from the box find the probability that it bears 1) a number divisible by 5
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Answer:
3/13
Step-by-step explanation:
n(S)=70-6+1
=65
n(A) = 70/5 - 10/5 + 1
=16-2+1
=15
P(A)= n(A)/n(S)
= 15/65
=3/13
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