Question

a box containes 6 red ,4 white ,5black balls a person draws 4 balls from the box at random find the probablity that among the balls drawn is atleast one balls of each other​

Answer 1

Step-by-step explanation:

6 Red, 5 Black, 4 White

Total 1 5 balls out of which 4 balls to be drawn. Total combinations= 15c4 = 1365 ways There will be 3 possibilities.

1. Two red balls, 1 black, 1 white 2 Red.. 62 15, 1 black.. 5c1=5.1 wihi..... 4c1=4

Total= 15*5*4=300

1. Two black balls, 1 red, 1 white 2 Black.... 5c2 10, 1 red....66 = 6.1 wih...... 4c1-4

Total= 10*6*4: 240

1. Two white balls, 1 red, 1 black 2 White....442 =6, 1 black..... 5c1=5. 1 r...... 6c1-6

Total= 6*5*4 =180

So the required probability is (300+240+180)/1365 = 720/1365

48/91