A box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains exactly one defective bulb.
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Answered by
22
Hi dr. ......Gud mrng. ....
EXPLANATION:
Total number of elementary events = 10C5
Number of ways of selecting exactly one defective bulb out of 3 and 4 non-defective out of 7 is 3C1*7C4
So,required probability =3C1*7C4/10C5 = 5/12.
HOPE THIS HELPS.....
@harsha889
EXPLANATION:
Total number of elementary events = 10C5
Number of ways of selecting exactly one defective bulb out of 3 and 4 non-defective out of 7 is 3C1*7C4
So,required probability =3C1*7C4/10C5 = 5/12.
HOPE THIS HELPS.....
@harsha889
Answered by
5
Answer:
Step-by-step explanation:
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