A box contains 10 Lamps of
which 6 are in good condition. A
room contains three sockets find
the probability that there is light
4/120
O 1/3
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Answer:
There are 3 possibilities :
Either we get 1 correct bulb, or 2 or 3.
Hence total chances of
having a light = [3( 6 C 2 × 4 C 1 )+3( 6 C 1 × 4 C 2 )+ 4 C 3 ]/ 10 C 3 = 65
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