Math, asked by Tanjila123, 10 months ago

A box contains 10 light bulbs and 2 of the 10 bulbs are defective. 3 of the 10 bulbs are taken randomly from the box. Find the probability that there is exactly 1 defective bulb out of the 3 bulbs taken from the box

Answers

Answered by amitnrw
0

7/15 is the  probability that there is exactly 1 defective bulb out of the 3 bulbs taken from the box if 2 of the 10 bulbs are defective

Step-by-step explanation:

Total bulbs = 10

Defective = 2

non - Defective = 8

3 Bulbs selected and we need to find the probability that there is exactly 1 defective bulb

There can be 3 cases

1st bulb is defective

2nd bulb is defective

3rd bulb is defective

Probability  1st bulb is defective =  (2/10)(8/9)(7/8)   =  7/45

Probability  2nd bulb is defective =  (8/10)(2/9)(7/8)   =  7/45

Probability 3rd  bulb is defective =  (8/10)(7/9)(2/8)   =  7/45

Total probability = 7/45 + 7/45 + 7/45 =  7/15

Another way

P(1)  = ³C₁(2/10)¹(8/10)²  = 12/25 ( but it works where Volume is high & Probability of defective & non-defective remains constant)

Learn more about probability :

The probability that the assembled part will not be defective, is

https://brainly.in/question/9425730

f the probability of selecting a defective bolt is 0.1

https://brainly.in/question/11773467

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