Question

A box contains 10 white beads and 15 green beads. They are mixed thoroughly
and one bead is drawn at random. What is the probability of getting a) white bead
b) a green bead?

Answer 1

1. 10/25-2/5
2. 15/25-3/5

Step-by-step explanation:

hope so it will help

Answer 2

Given :

• A box contains 10 white beads and 15 green beads.
• They are mixed thoroughly and one bead is drawn at random.

To Find :

Probability of getting :

• A White bead
• A Green Bead

Solution :

Analysis :

Here we first have to add both the green and the white beads. As it is said that one bead is drawn at a random therefore we have to divide the particular bead by total number of beads.

Required Formula :

$\boxed{\bf P(E) = \dfrac{No\ of\ favourable\ outcomes}{Total\ no\ of\ possible\ outcomes}}$

• P(E) = The particular event

Explanation :

A white Bead :

• Total no of outcomes = 10 + 15 = 25
• Favourable outcomes = 10

We know that if we are given the favourable outcomes and the total no of outcomes and is asked to find the probability then our required formula is,

$\bf P(E) = \dfrac{No\ of\ favourable\ outcomes}{Total\ no\ of\ possible\ outcomes}$

where,

• P(E) = Getting white bead
• No of favourable outcomes = 10
• Total no of outcomes = 25

Using the required formula and substituting the required values,

$\\ :\implies\sf P_{(getting\ a\ white\ bead)} = \dfrac{10}{25}$

$\\ :\implies\sf P_{(getting\ a\ white\ bead)} = \dfrac{\not{1}\!\!\!\not{0}\ \ ^2}{\not{2}\!\!\!\not{5}\ \ ^5}$

$\\ :\implies\sf P_{(getting\ a\ white\ bead)} = \dfrac{2}{5}$

$\\ \therefore\boxed{\bf P_{(getting\ a\ white\ bead)} = \dfrac{2}{5}.}$

____________________________

A green Bead :

• Total no of outcomes = 10 + 15 = 25
• Favourable outcomes = 15

We know that if we are given the favourable outcomes and the total no of outcomes and is asked to find the probability then our required formula is,

$\bf P(E) = \dfrac{No\ of\ favourable\ outcomes}{Total\ no\ of\ possible\ outcomes}$

where,

• P(E) = Getting green bead
• No of favourable outcomes = 15
• Total no of outcomes = 25

Using the required formula and substituting the required values,

$\\ :\implies\sf P_{(getting\ a\ white\ bead)} = \dfrac{15}{25}$

$\\ :\implies\sf P_{(getting\ a\ white\ bead)} = \dfrac{\not{1}\!\!\!\not{5}\ \ ^3}{\not{2}\!\!\!\not{5}\ \ ^5}$

$\\ :\implies\sf P_{(getting\ a\ white\ bead)} = \dfrac{3}{5}$

$\\ \therefore\boxed{\bf P_{(getting\ a\ white\ bead)} = \dfrac{3}{5}.}$

Probability of getting a white bead is 2/5.

Probability of getting a green bead is 3/5.

Explore More :

• Experiment :

An action which results in some (well–defined) outcomes is called an experiment.

• Random Experiment :

An experiment is called random if it has more than one possible outcome and it is not possible to tell (predict) the outcome in advance.