Question

A box contains 100 items of which 4 are defective. Two items are chosen at random from the box. What is the probability of selecting
(a) 2 defectives if the first item is not replaced;
(b) 2 defectives if the first item is put back before
choosing the second item;

Answer 1

Answer:

he final answer is "0.0012, and  0.0016.

Step-by-step explanation:

A probability is an amount that reflects these same probabilities. Probabilities can be expressed in percentages from 0 to 1, as well as in proportions from 0 to 100 %.

Following are calculations of the given points:

A)

P(2 Defectives )= 4/100×3/99 =0.0012

 

B)

p( 2 defectives) = 4/100 × 4/100 = 0.0016

So, the final answer is "0.0012, and  0.0016.