A box contains 12 ball of which some are red.If 6 more red balls are put in the box and a ball is drawn at random, the probability of drawing a red ball doubles than what it was before.Find the number of red balls in the bag
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Solution :-
Let the total number of red balls initially be x
Total number of balls in the box = 12
P(getting a red ball) = x/12
Now, 6 red balls are put in the box, then the total number of balls
= 12 + 6
= 18 balls
Then total number of red balls = (x + 6)
Now,
P(getting a red ball) = (x + 6)/18
According to the question.
2(x/12) = (x + 6)/18
2x/12 = (x + 6)/18
Cross multiplying
⇒ 36x = 12x + 72
⇒ 36x - 12x = 72
⇒ 24x = 72
x = 3
So, initially the number of red balls in the box were 3
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