A box contains 12 balls of which some are red in colour . If 6 more red balls are put in the box and a ball is drawn at random the probability of drawing a red ball doubles that what it was before .find the number of red balls in the bag.
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18 red balls are left in the box.
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❥let the red balls initially be x
❥probability = x/12
❥after 6 red balls have been added, probability becomes (6+x)/18.
❥now according to the question it becomes twice the initial value.
(6+x)/18 = 2 × x/12
❥solving this we get x = 3.
❥initially there were 3 red balls
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