A box contains 12 balls of which some are red in colour if 6 more red balls are put in the box and a ball is drawn at random, the probability of drawing a red ball doubles than what it was before. Find the number of red balls in the box.
Answers
Answered by
3
let the no. of red balls be x
now 6 more red balls are in the box
so total no of balls =18
no of red balls are 6+x
so acc to qus
new probability=2 (before probability)
(6+x/18)=(x/12)2
(6+x)/18=x/6
6(6+x)=18x
36+6x=18x
36=12x
x=3
so total no of red balls be (6+3)
=9
hope it will help you
now 6 more red balls are in the box
so total no of balls =18
no of red balls are 6+x
so acc to qus
new probability=2 (before probability)
(6+x/18)=(x/12)2
(6+x)/18=x/6
6(6+x)=18x
36+6x=18x
36=12x
x=3
so total no of red balls be (6+3)
=9
hope it will help you
Answered by
5
Let number of red balls be = x
P(red ball) = x/12
If 6 more red balls are added:
The number of red balls = x + 6
P(red ball) = (x+6)/18
Since, (x+6)/18 = 2(x/12)
x = 3
Therefore, there are 3 red balls in the bag.
P(red ball) = x/12
If 6 more red balls are added:
The number of red balls = x + 6
P(red ball) = (x+6)/18
Since, (x+6)/18 = 2(x/12)
x = 3
Therefore, there are 3 red balls in the bag.
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