A box contains 12 balls of which some are red in colour. If 6 more red balls are put in the box and a ball is drawn at random,the probability of drawing a rd ball doubles than what it was before . then what is the probability of getting a red ball
Answers
Answered by
0
Answer:
1/4
Step-by-step explanation:
Let the initial number of red balls be x
The probability of getting a red ball will be :
x/12
When 6 red balls are added the total number of balls become :
12 + 6 = 18
The probability of getting a red ball becomes :
(x + 6)/18
From the question :
2(x/12) = (x + 6)/18
2x /12 = (x + 6)/18
18(2x) = 12(x + 6)
36x = 12x + 72
36x - 12x = 72
24x = 72
x = 3
The probability of getting a red ball is thus :
3/12 = 1/4
Answered by
0
Answer:
1/4
Step-by-step explanation:
Let the initial number of red balls be x
The probability of getting a red ball will be :
x/12
When 6 red balls are added the total number of balls become :
12 + 6 = 18
The probability of getting a red ball becomes :
(x + 6)/18
From the question :
2(x/12) = (x + 6)/18
2x /12 = (x + 6)/18
18(2x) = 12(x + 6)
36x = 12x + 72
36x - 12x = 72
24x = 72
x = 3
The probability of getting a red ball is thus :
3/12 = 1/4
1/4
Step-by-step explanation:
Let the initial number of red balls be x
The probability of getting a red ball will be :
x/12
When 6 red balls are added the total number of balls become :
12 + 6 = 18
The probability of getting a red ball becomes :
(x + 6)/18
From the question :
2(x/12) = (x + 6)/18
2x /12 = (x + 6)/18
18(2x) = 12(x + 6)
36x = 12x + 72
36x - 12x = 72
24x = 72
x = 3
The probability of getting a red ball is thus :
3/12 = 1/4
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