a box contains 12 balls out of which X are black if one ball is drawn at random from the box what is the probability that it will be a black ball if 6 more black balls are put in the box the probability of drawing a black ball now is double of what it was before find x
Answers
Answered by
1
Step-by-step explanation:
first case
p(black) = x/12
second case
p(black) = (x+6)/18
according to question
(x+6)/18 = 2*x/12
by cross multiplication
12*(x+6)=18*2*x
12x + 72 = 36x
72 = 36x-12x
72 = 24x
x=3
so the value of x is 3
hope u got it।।।।
Answered by
1
Step-by-step explanation:
P(B)=X/12
now on adding 6 more black balls.
P(B)=(X+6)/18
thus acc to qs
(X+6)/18=2*(X/12)
implies that X=3
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