A box contains 12 balls out of which x are black. If one ball is drawn at random from
the box, what is the probability that it will be a black ball ? If 6 more black balls are put in
the box, the probability of drawing a black ball now is double of what it was before. Find x.
Answers
Answered by
613
Total number of balls = 12
Total number of black balls = x
P (getting a black ball) = x/12
If 6 more black balls are put in the box, then
Total number of balls = 12 + 6 = 18
Total number of black balls = x + 6
P (getting a black ball now) = x + 6 /18
Atq,
2(x/12) = ( x+. 6 /18)
3x = x+6
2x=6
x = 3
plzz mark as brainliest answer !!!
Total number of black balls = x
P (getting a black ball) = x/12
If 6 more black balls are put in the box, then
Total number of balls = 12 + 6 = 18
Total number of black balls = x + 6
P (getting a black ball now) = x + 6 /18
Atq,
2(x/12) = ( x+. 6 /18)
3x = x+6
2x=6
x = 3
plzz mark as brainliest answer !!!
Answered by
5
Answer:
Total number of balls = 12
Total number of black balls = x
P (getting a black ball) = x/12
If 6 more black balls are put in the box, then
Total number of balls = 12 + 6 = 18
Total number of black balls = x + 6
P (getting a black ball now) = x + 6 /18
Atq,
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